SOLUTION: 30. There are four auto body shops in a community and all claim to promptly serve customers.
To check if there is any difference in service, customers are randomly selected from e
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To check if there is any difference in service, customers are randomly selected from e
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Question 136371: 30. There are four auto body shops in a community and all claim to promptly serve customers.
To check if there is any difference in service, customers are randomly selected from each
repair shop and their waiting times in days are recorded. The output from a statistical software
package is:
Summary
Groups Count Sum Average Variance
Body Shop A 3 15.4 5.133333 0.323333
Body Shop B 4 32 8 1.433333
Body Shop C 5 25.2 5.04 0.748
Body Shop D 4 25.9 6.475 0.595833
ANOVA
Source of Variation SS df MS F p-value
Between Groups 23.37321 3 7.791069 9.612506 0.001632
Within Groups 9.726167 12 0.810514
Total 33.09938 15
Is there evidence to suggest a difference in the mean waiting times at the four body shops?
Use the .05 significance level.
Please help Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! There are four auto body shops in a community and all claim to promptly serve customers.
To check if there is any difference in service, customers are randomly selected from each repair shop and their waiting times in days are recorded. The output from a statistical software package is:
Summary
Groups Count Sum Average Variance
Body Shop A 3 15.4 5.133333 0.323333
Body Shop B 4 32 8 1.433333
Body Shop C 5 25.2 5.04 0.748
Body Shop D 4 25.9 6.475 0.595833
--------------------------------------------
ANOVA
Source of Variation SS df MS F p-value
Between Groups 23.37321 3 7.791069 9.612506 0.001632
Within Groups 9.726167 12 0.810514
Total 33.09938 15
Is there evidence to suggest a difference in the mean waiting times at the four body shops?
Use the .05 significance level.
Please help
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Ho: The mean waiting times are the same for the four body shops
Ha: At least one of the means is different
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ANOVA was run on the data.
The p-value of 0.001632 is less than alpha=5% so Reject Ho.
The test supports a conclusion that the average waiting times
are not all the same.
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Cheers,
Stan H.
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