SOLUTION: Elliot began the journey at 8am at 40 kilometers per hour. Benita began to chase him at 11 am at 50 kilometers per hour. What time was it when Bernita got within 60 kilometers of E
Algebra ->
Probability-and-statistics
-> SOLUTION: Elliot began the journey at 8am at 40 kilometers per hour. Benita began to chase him at 11 am at 50 kilometers per hour. What time was it when Bernita got within 60 kilometers of E
Log On
Question 122320: Elliot began the journey at 8am at 40 kilometers per hour. Benita began to chase him at 11 am at 50 kilometers per hour. What time was it when Bernita got within 60 kilometers of Elliot? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Elliot began the journey at 8 am at 40 kilometers per hour. Benita began to chase him at 11 am at 50 kilometers per hour. What time was it when Bernita got within 60 kilometers of Elliot?
:
Let x = travel time of E, when he's 60 km ahead of B
Then
(x-3) = travel time of B, when he's with 60 km behind (started 3 hrs later)
:
Write a distance equation: Distance = speed * time
:
E's distance - B's distance = 60
40x - 50(x-3) = 60
40x - 50x + 150 = 60
-10x = 60 - 150
-10x = -90
x =
x = + 9 hrs (after 8 AM)
:
AT 5 PM, B is within 60 km of E
:
Check solutions by finding the distance traveled by both
40*9 = 360 km
50*6 = 300 km (started 3 hrs later)
----------
diff = 60 km