SOLUTION: Find the constant term in the binomial expansion of (4𝑥^3 − 1/2𝑥^2)^15.

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Question 1205236: Find the constant term in the binomial expansion of (4𝑥^3 − 1/2𝑥^2)^15.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find the constant term in the binomial expansion of (4𝑥^3 − 1/2𝑥^2)^15.
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There is NO constant term in this binomial expansion, at all.

In other words, the constant term is 0 (zero) in this binomial expansion.


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Couple of my comments regarding the post by @greenestamps.

    (a)   I totally agree that the "The problem is posted incorrectly."

    (b)   I disagree that  " The sequence of characters "1/2x^2" is ambiguous. "


It is not ambiguous.  It has only  ONE  meaning - exactly as it is written in the post.

Another thing that this meaning is opposite to that the normal problem must say;
but it is just  highlight%28highlight%28ENTIRELY%29%29  the  highlight%28highlight%28fault%29%29  of the  highlight%28highlight%28visitor%29%29.

It is not an ambiguity,  in no case  ( ! ).   It is wrong writing and wrong presentation of the problem,
and it can not be treated differently.



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The problem is posted incorrectly.

The sequence of characters "1/2x^2" is ambiguous.

If that means %281%2F2%29x%5E2, then there is of course no constant term in the expansion.

But if it means (as it surely was intended to!) 1%2F%282x%5E2%29, then there is a constant term.

Any student who is working on a problem like this should have enough experience with mathematics to know that proper use of parentheses is important.

Assuming the latter meaning, the constant term will occur when the 4x%5E3%29 term is to the 6th power and the 1%2F%282x%5E2%29 term is to the 9th power. That constant term is



ANSWER: -40040