SOLUTION: The television show Found has been successful for many years. That show recently had a share of 28, which means, that among the TV sets in use, 28% were tuned to Found. An adverti
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-> SOLUTION: The television show Found has been successful for many years. That show recently had a share of 28, which means, that among the TV sets in use, 28% were tuned to Found. An adverti
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Question 1203041: The television show Found has been successful for many years. That show recently had a share of 28, which means, that among the TV sets in use, 28% were tuned to Found. An advertiser wants to verify that 28% share value by conducting its own survey, and a pilot survey begins with 14 households have TV sets in use at the time of a Found broadcast.
Find the probability that none of the households are tuned to Found.
P(none) =
Find the probability that at least one household is tuned to Found.
P(at least one) =
Find the probability that at most one household is tuned to Found.
P(at most one) =
If at most one household is tuned to Found, does it appear that the 28% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Found unusual?)
no, it is not wrong
yes, it is wrong Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! this looks like a binomial distribution.
assuming that it is, i get:
getting a sample with 0 or 1 household out of 14 tuned to the television show FOUND would occur an average of approximately 6.5% of the time.
getting a sample with 1 or more households out of 14 tuned to the television show FOUND would occur an average of approximately 99% of the tie.
based on this, the occurrence of a sample where no more than 1 household out of 14 is watching the show FOUND would be most unusual.
here's the distribution of the probabilities from excel.
