SOLUTION: In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group?

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Question 1201763: In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group?
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

n = 83 = sample size
phat = 0.301 = sample proportion

SE = standard error of the proportion
SE = sqrt(phat*(1-phat)/n)
SE = sqrt(0.301*(1-0.301)/83)
SE = 0.0503480656
That value is approximate.
Round it however needed.