Question 1201698: An urn contains 8 orange balls and 4 green balls. If Vince chooses 5 balls at random from the urn, what is the probability that he will select 3 orange balls and 3 green balls? Round your answer to 3 decimal places.
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
ANSWER: 0
He can't get 3 orange balls and 3 green balls if he chooses only 5 balls from the bag....
To set up the problem for solving, I will assume that he picked 6 balls from the bag instead of 5.
The possible outcomes are all the ways he can choose 6 of the 12 balls.
The good outcomes are the ways he can choose 3 of the 8 orange balls and 3 green balls.
C(8,3) * C(4,3)
P(3 of 8 orange AND 3 of 4 green) = -----------------
C(12,6)
Use a calculator; and round the answer as directed....
|
|
|
