Question 1200588: A symmetric coin is tossed n times, the outcomes are denoted by letters H, S. With a letter of length n, the sequence is shortened by crossing out all letters H before the first S and all H after the last S (if any). What is the probability that the resulting truncated sequence will contain no more than the letter m? ([n, m] = [14, 4])
Answer by ikleyn(52776)   (Show Source):
You can put this solution on YOUR website! .
A symmetric coin is tossed n times, the outcomes are denoted by letters H, S. With a letter of length n,
the sequence is shortened by crossing out all letters H before the first S and all H after the last S (if any).
What is the probability that the resulting truncated sequence will contain no more than the letter m? ([n, m] = [14, 4])
~~~~~~~~~~~~~~~~~
Read your post attentively and try to understand why it is failed,
why it makes no sense, why it is incorrect and where is the error.
When you will get it, fix and re-write your post.
After that, re-post to the forum.
Please do not post it to me personally.
|
|
|
