SOLUTION: Rounded to 2 decimal places, solve for k (the z-score) such that P(−k < z < k) = 0.17 k=

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Question 1197776: Rounded to 2 decimal places, solve for k (the z-score) such that
P(−k < z < k) = 0.17
k=

Found 2 solutions by math_tutor2020, ewatrrr:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Answer: k = 0.21

Explanation:

There are many free online Z score calculators to use.
I recommend this one as it offers a diagram
https://davidmlane.com/normal.html
Click on the radio button "Value from an area"
Then type 0.17 into the "area" box. Leave the mean and SD as 0 and 1 respectively.

Then click on the "between" radio button to have "-0.214 and 0.214" show up.
You might have to click "recalculate".

This tells us that P(-0.214 < z < 0.214) = 0.17 approximately

When rounding to two decimal places, we write
P(-0.21 < z < 0.21) = 0.17
which shows k = 0.21



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

wanting the area on either side of z = 0 to be .17/2 = .085
.085 + .5(area to the left of z = 0)
k = Invnorm(.585) = .21
P(−21 < z < .21) = 0.17