SOLUTION: A psychiatrist is interested in finding a 98% confidence interval for the tics per hour exhibited by children with Tourette syndrome. The data below show the tics in an observed ho

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Question 1197537: A psychiatrist is interested in finding a 98% confidence interval for the tics per hour exhibited by children with Tourette syndrome. The data below show the tics in an observed hour for 13 randomly selected children with Tourette syndrome. Round answers to 3 decimal places where possible.

8 1 2 4 0 7 8 9 3 7 0 3 4
a. To compute the confidence interval use a
?
distribution.
b. With 98% confidence the population mean number of tics per hour that children with Tourette syndrome exhibit is between
and
.
c. If many groups of 13 randomly selected children with Tourette syndrome are observed, then a different confidence interval would be produced from each group. About
percent of these confidence intervals will contain the true population mean number of tics per hour and about
percent will not contain the true population mean number of tics per hour.

Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi 'Standard Distribution': µ = 4.307 and σ = 3.172 (Used Calculator- both rounded) n = 13 98% confidence interval: z = 2.236 | Invnorm(.98 + .02/2) = Invnorm(.99) = 2.046 4.307 - 2.046< < 4.307 + 2.046 2.261 < < 6.353 98% confident, interval will contain true population mean Wish You the Best in your Studies.