SOLUTION: The line width of a tool used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer. (a)

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Question 1197391: The line width of a tool used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer.
(a) What is the probability that a line width is greater than
0.62 micrometer?
(b) What is the probability that a line width is between 0.47 and 0.63 micrometer?
。
(c) The line width of 90% of samples is below what value?
Found 2 solutions by ewatrrr, Alan3354:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi Normal Distribution: µ = .5 and σ = .05 Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus normalcdf(smaller value, larger value, µ, σ). P(x >.62 ) = normalcdf( .62, 9999, .5, .05) = .0082 P(.47 ≤ x ≤ .63) = normalcdf( .47, .63, .5, .05) = .7211 The line width of 90% of samples is below what value z= Invnorm(.90) = 1.28 = .05(1.28) + .5 Recommend Using stattrek.com to check Results until You are familiar with Using Your Calculator. Trusting Your Use of Your calculator is key to success working with Distributions. Wish You the Best in your Studies.

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
A millionth of a meter is called a micron, not a micrometer.
A micrometer is a measuring instrument.
I have bought several micrometers.