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Hi  
Binomial Probability:  n = 6, p(recover) = .75, p(die) = .25
what then is the probability that the inspector's sample contains:
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
P(2 die) =.2966
0r
 P(2die) = 15(.25^2)(.75^4) =.2966
P(x = 4 recover ) = .2966
0r
 
 P(2die) = 15(.25^2)(.75^4) =.2966
P(x = 4 recover ) = .2966
0r  P(4 recover) = 15(.75^4)(.25^2) =.2966
Wish You the Best in your Studies.
 
P(4 recover) = 15(.75^4)(.25^2) =.2966
Wish You the Best in your Studies.