SOLUTION: The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 315 grams and a standard deviation of 16 grams. Find the weight that corresponds to
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Question 1197070: The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 315 grams and a standard deviation of 16 grams. Find the weight that corresponds to each event. (Round your final answer to 2 decimal places.)
a)Highest 20 percent_____
b)Middle 60 percent____ to ____
c)Highest 80 percent____
d)Lowest 15 percent____ Answer by ewatrrr(24785) (Show Source):
Hi
Recommend the use of a calculator and understanding of the standard normal curve
Normal Distribution: µ = 0 and σ = 1
z score represents the area under the curve to the LEFT of its value
Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
Calculator function Invnorm(X) gives value to the LEFT of z
Highest 20 percent |z= Invnorm(80%) = .84 (to 2 decimal places)
| weight > 328.44
Middle 60% |z= Invnorm(20%) = -.84 (to 2 decimal places)
Middle 60%: -.84 to .84
|
|
weight from: 314.46 to 328.44 lbs
Highest 80 percent: > 314.26 lbs
Lowest 15 percent: |z= Invnorm(15%) = -1.04 | weight ≤ 298.36 lbs
Wish You the Best in your Studies.