| 
 
 
| Question 1197054:  Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure. Suppose the target tire pressure of a certain car is 32 psi (pounds per square inch.)
 a)At what psi will the TPMS trigger a warnig for this car? (Round your answer to 2 decimal points.)
 b)Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 3 psi. If the car's average tire pressure is on target, what is the probability that the TPMS will trigger a warning? (Round your answer to 4 decimal places.)
 c)The manufacturer's recommended correct inflation range is 30 psi to 34 psi. Assume the tire's average psi is on target. If a tire on the car is inspected at random, what is the probability that the tire's inflation is within the recomended range? (Round your intermediate calculations and final answer to 4 decimal places.)
 Answer by Theo(13342)
      (Show Source): 
You can put this solution on YOUR website! a)At what psi will the TPMS trigger a warnig for this car? (Round your answer to 2 decimal points.) 
 target pressure = 32 psi.
 28% below 32 = (1 - .28) * 32 = 23.04 psi.
 when the target pressure gets below that, the tpms will warn the driver.
 
 b)Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 3 psi. If the car's average tire pressure is on target, what is the probability that the TPMS will trigger a warning? (Round your answer to 4 decimal places.)
 
 with a mean of 32 and a standard deviation of 3, the probability that the tpms will trigger a warning will be based on the following formula.
 z = (x - m) / s
 z is the z-score
 x is the raw score
 m is the mean
 s is the standard deviation.
 when x = 23.04 and m = 32 and s = 3, the formula becomes:
 z = (23.04 - 32) / 3 = -2.9867 rounded to 4 decimal places.
 probability of getting a z-score less than that is equal to .0014.
 
 c)The manufacturer's recommended correct inflation range is 30 psi to 34 psi. Assume the tire's average psi is on target. If a tire on the car is inspected at random, what is the probability that the tire's inflation is within the recommended range? (Round your intermediate calculations and final answer to 4 decimal places.)
 
 z-score for psi of 30:
 z = (30 - 32) / 3 = -.6667 rounded to 4 decimal places.
 z-score for psi of 45:
 z = (34 - 32) / 3 = .6667 rounded to 4 decimal places.
 probability of getting a z-score less than -.6667 is equal to .2525 rounded to 4 decimal places.
 probability of getting a z-score less than .6667 is equal to .7475 rounded to 4 decimal places.
 probability of getting a z-score between -.6667 and .6667 is equal to .7475 minus .2524 = .4950.
 
 
 
 
 
 
 
 
 
 
 | 
  
 | 
 |