Question 1195504: How many 5-digit numbers can be formed using numbers 0, 1, 2, …9, such that repetition is NOT allowed
Found 2 solutions by ikleyn, Alan3354: Answer by ikleyn(52778) (Show Source):
You can put this solution on YOUR website! .
How many 5-digit numbers can be formed using numbers 0, 1, 2, …9, such that repetition is NOT allowed
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Any of 9 digits at the most-left position, giving 9 possible options;
(any of ten digits, except of 0);
Any of remaining 10-1 = 9 digits at the next position, giving 9 possible options;
Any of remaining 9-1 = 8 digits at the next position, giving 8 possible options;
Any of remaining 8-1 = 7 digits at the next position, giving 7 possible options;
Any of remaining 7-1 = 6 digits at the next position, giving 6 possible options.
Thus in total, there are 9*9*8*7*6 = 27216 different 5-digit numbers as described.
Solved, answered and explained.
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The lesson to learn from my solution is that a leading digit can not be 0 (zero).
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! You should specify whether 0 can be the leading digit. There's no rule that it cannot.
For example, James Bond is agent 007.
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Also, 12.345 is a 5 digit number.
And, so is -12345.
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