Question 1194633: 3. Construct a table listing all possible samples of size 7
Combination: 87, 92, 93, 93, 94, 94, 95, 96, 97
Must be 36 samples
Found 2 solutions by greenestamps, math_tutor2020: Answer by greenestamps(13198) (Show Source):
You can put this solution on YOUR website!
That's a job that you can do yourself; we aren't going to do all the tedious work for you....
You are choosing 7 of the 9 elements in the set; the number of combinations is C(9,7) = 36.
The number C(9,7) is the same as the number C(9,2) -- each group of 7 of the 9 that you choose corresponds to a group of 2 that you do NOT choose.
Use that idea to make it easier to make your list. Make a list of each group of 2 you can NOT choose and find the corresponding group of 7 for your list. For example....
not chosen chosen
(group of 2) (group of 7)
----------------------------------------
87, 92 93, 93, 94, 94, 95, 96, 97
93, 93 87, 92, 94, 94, 95, 96, 97
94, 97 87, 92, 93, 93, 94, 95, 96
... ...
Answer by math_tutor2020(3816) (Show Source):
You can put this solution on YOUR website!
As the other tutor mentioned, you can form subsets of size 7 by picking subsets of size 2.
Whatever 2 items you pick, they will be ignored so you can focus on the other 7 items.
Because this value 2 shows up, it may be handy to form a two-way table. In this case, we'll have a 9 row and 9 column two-way table like this.
| 87 | 92 | 93 | 93 | 94 | 94 | 95 | 96 | 97 | 87 | | | | | | | | | | 92 | | | | | | | | | | 93 | | | | | | | | | | 93 | | | | | | | | | | 94 | | | | | | | | | | 94 | | | | | | | | | | 95 | | | | | | | | | | 96 | | | | | | | | | | 97 | | | | | | | | | |
Write X's along the main diagonal.
This is because we cannot select the same item twice when forming a 2 element subset.
| 87 | 92 | 93 | 93 | 94 | 94 | 95 | 96 | 97 | 87 | X | | | | | | | | | 92 | | X | | | | | | | | 93 | | | X | | | | | | | 93 | | | | X | | | | | | 94 | | | | | X | | | | | 94 | | | | | | X | | | | 95 | | | | | | | X | | | 96 | | | | | | | | X | | 97 | | | | | | | | | X |
We'll also write X's in every entry below the diagonal.
Why? Notice that stuff below the diagonal mirrors the stuff above the diagonal.
Example: look at row 2, column 1 and you'll see we're dealing with the same values as row 1, column 2. Both of those values being 87 and 92 in either order.
| 87 | 92 | 93 | 93 | 94 | 94 | 95 | 96 | 97 | 87 | X | | | | | | | | | 92 | X | X | | | | | | | | 93 | X | X | X | | | | | | | 93 | X | X | X | X | | | | | | 94 | X | X | X | X | X | | | | | 94 | X | X | X | X | X | X | | | | 95 | X | X | X | X | X | X | X | | | 96 | X | X | X | X | X | X | X | X | | 97 | X | X | X | X | X | X | X | X | X |
The empty cells that haven't been crossed out are then filled with the 7 element subsets
For example, in row 1, column 2 we'll have the subset {93, 93, 94, 94, 95, 96, 97} which is everything except the 87 & 92
| 87 | 92 | 93 | 93 | 94 | 94 | 95 | 96 | 97 | 87 | X | {93, 93, 94, 94, 95, 96, 97} | | | | | | | | 92 | X | X | | | | | | | | 93 | X | X | X | | | | | | | 93 | X | X | X | X | | | | | | 94 | X | X | X | X | X | | | | | 94 | X | X | X | X | X | X | | | | 95 | X | X | X | X | X | X | X | | | 96 | X | X | X | X | X | X | X | X | | 97 | X | X | X | X | X | X | X | X | X |
I'll let you fill out the rest.
Edit: I realize that there are duplicate entries (93 and 94). I'm not sure if your teacher made a typo or not. I'll keep my answer as is, since it may be useful for similar types of problems of this nature.
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