Question 1192061: The fill amount in 2-liter soft drink bottles is normally distributed, with a mean of 2.0 liters and a
standard deviation of 0.05 liter. If bottles contain less than 95% of the listed net content (1.90 liters, in
this case), the manufacturer may be subject to penalty by the state office of consumer affairs. Bottles
that have a net content above 2.10 liters may cause excess spillage upon opening. What proportion of
the bottles will contain
a. between 1.90 and 2.0 liters?
b. between 1.90 and 2.10 liters?
c. below 1.90 liters or above 2.10 liters?
d. At least how much soft drink is contained in 99% of the bottles?
e. 99% of the bottles contain an amount that is between which two values (symmetrically distributed) around
the mean?
I've solved the first four question, only need help with the last one.
Thanks.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 99% half-interval around the mean is z(0.995)*sigma/sqrt(n)
=2.576*0.05
=0.1288 or 0.13 l,
(1.87, 2.13) liters will be found in 99% of the bottles.
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