SOLUTION: According to Masterfoods, the company that manufactures M&Ms, 12% of peanut M&Ms are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. Assume that
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-> SOLUTION: According to Masterfoods, the company that manufactures M&Ms, 12% of peanut M&Ms are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. Assume that
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Question 1191704: According to Masterfoods, the company that manufactures M&Ms, 12% of peanut M&Ms are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. Assume that selecting multiple M&Ms are independent events. (Round your answers to three decimal places, for example 0.123)
Compute the probability that a randomly selected peanut M&M is not green.
Compute the probability that three randomly selected peanut M&Ms are all green.
If you randomly select four peanut M&Ms, compute the probability that none of them are red. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! p(not green) is 1-p(green)=0.85
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all three are green is 0.15^3=0.003375 or 0.003. Sorry, I was still thinking of complement.
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none red is 0.88^4=0.5997 or 0.600.
There is an 88% chance it won't be red.
