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Find P(E) under the assumption that P(E ∪ F) = 0.7 and P(E ∪ F^c) = 0.9
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Apply the basic formula of the probability theory for events (sets) A and B of the universal set X
P(A U B) = (P(A) + P(B) - P(A ∩ B).
You will get
P(E U F) = P(E) + P(F) - P(E ∩ F) (1)
and
P(E U F^c) = P(E) + P(F^c) - P(E ∩ F^c) (2)
Now add these equations (1) and (2). Substitute the given values P(E ∪ F) = 0.7 and P(E ∪ F^c) = 0.9.
You will get
0.7 + 0.9 = 2*P(E) + (P(F) + P(F^c)) - (P(E ∩ F) + P(E ∩ F^c)). (3)
Now take into account that P(F) + P(F^c) = 1 and P(E ∩ F) + P(E ∩ F^c) = P(E).
You will get then from (3)
1.6 = 2*P(E) + 1 - P(E).
Combining like terms, you get the ANSWER : P(E) = 0.6.
Solved.