SOLUTION: . A box contains four black and six white balls. What is the probability of getting two black balls in drawing one after the other under the following conditions? a. The first ba

Question 1190739: . A box contains four black and six white balls. What is the probability of getting two black balls
in drawing one after the other under the following conditions? a. The first ball drawn is not
replaced
b. The first ball drawn is replaced

Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
.
A box contains four black and six white balls. What is the probability of getting two black balls
in drawing one after the other under the following conditions?
(a) The first ball drawn is not replaced
(b) The first ball drawn is replaced
~~~~~~~~~~~~~~~

4 + 6 = 10  total balls.


(a)  P =  =  =  = 0.133333... = 13.33%  (rounded).    ANSWER



(b)  P =  =  = 0.16 = 16%.    ANSWER

Solved.

The formulas in the post are SELF-EXPLANATORY.

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