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Consider two sets A and B such that A⊆B.
Find the possible values of X if A = {2,4,5,x} and B = {2,3,5,6, x+1}.
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To solve this problem, you should apply some logic.
The logic works this way:
(1) x is NEVER EQUAL to x+1; therefore, x and x+1 represent different elements; they can not represent the same element.
(2) THEREFORE, x of the set A can be and should be one of the explicitly listed elements 2, 3, 5, 6 of the set B.
(3) From the other side, x can not repeat the existing elements 2, 4, 5 of the set A.
(4) It leaves only values 3 or 6 for x.
(5) Now you should check both these possibilities.
If x is 3, then A = {2,4,5,3} and B = {2,3,5,6,4}, which is consistent with the condition A⊆B .
If x is 6, then A = {2,4,5,6} and B = {2,3,5,6,7}, which is NOT CONSISTENT with the condition A⊆B ,
since then the element 4 does belong to A, but does not belong to B.
Thus this check leaves only one UNIQUE possibility for x to be 3.
ANSWER. x is 3.
Solved.