SOLUTION: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 4. Find the probability that a

Algebra ->  Probability-and-statistics -> SOLUTION: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 4. Find the probability that a       Log On


   



Question 1186328: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of the waiting time is 4. Find the probability that a person will wait for between 7 and 8 minutes. Round your answer to four decimal places.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
variance is 4 min^2 so sd=2 min
z=(x-mean)/sd
z=1/2 and 1
that probability z is between those values is 0.1499.