SOLUTION: A distribution of values is normal with a mean of 63.6 and a standard deviation of 14.4.
Find the probability that a randomly selected value is greater than 44.9.
P(X > 44.9) =
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-> SOLUTION: A distribution of values is normal with a mean of 63.6 and a standard deviation of 14.4.
Find the probability that a randomly selected value is greater than 44.9.
P(X > 44.9) =
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Question 1185731: A distribution of values is normal with a mean of 63.6 and a standard deviation of 14.4.
Find the probability that a randomly selected value is greater than 44.9.
P(X > 44.9) = Answer by Theo(13342) (Show Source):