SOLUTION: In a simple random sample of 1000 people, 261 are left-handed. Find a 95% confidence interval for the true proportion of left-handed people in the entire population
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Question 1184668: In a simple random sample of 1000 people, 261 are left-handed. Find a 95% confidence interval for the true proportion of left-handed people in the entire population Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the half interval is z(0.975)*sqrt(.261*.739/1000)=1.96*0.0139=0.0272
the interval is 0.261+/-0.0272
(0.234, 0.288)
