SOLUTION: Life insurance salesman meets his prospective customers separately. At each meeting, he makes the same effort to persuade the prospective client to be insured. The vendor's un

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Question 1183651:
Life insurance salesman meets his prospective customers separately. At each meeting, he makes the same effort to persuade the prospective client to be insured. The vendor's understanding after a long term in the insurance business is that the probability of persuading the customer to be insured (probability of success) is 0,1. What is the probability in 4 trials to insure one of them?
Answer by ikleyn(52946) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is the binomial distribution probability problem.


The formula and the answer are


    P = C%5B4%5D%5E1%2A0.1%5E1%2A%281-0.1%29%5E3 = 4%2A0.1%2A0.9%5E3 = 0.2916.

Solved.

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To see many other similar  (and different)  solved problems on the binomial distribution,  look into the lessons
    - Simple and simplest probability problems on Binomial distribution
    - Typical binomial distribution probability problems
in this site.