Question 1178561: Samuel has two 4-sides dice. the sides of each die have the numbers 1,2,3,4. because the dice are pyramid-shaped,
when Samual rolls the dice, each lands with three faces showing and one face not showing.
if Samual rolls his dice, the probability that the number not showing have a difference of 2 is:
a. 1/9
b. 1/8
c. 1/4
d. 1/3
Found 3 solutions by MathLover1, ikleyn, greenestamps:
Answer by MathLover1(20850)   (Show Source):
Answer by ikleyn(52879)  (Show Source):
You can put this solution on YOUR website! .
Samuel has two 4-sides dice. the sides of each die have the numbers 1,2,3,4. because the dice are pyramid-shaped,
when Samual rolls the dice, each lands with three faces showing and one face not showing.
if Samual rolls his dice, the probability that the number not showing have a difference of 2 is:
a. 1/9
b. 1/8
c. 1/4
d. 1/3
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Hello, this passage in your post
" . . . the number not showing have a difference of 2 . . ."
is NONSENSE.
It implies that the post in whole is NONSENSE, too.
Answer by greenestamps(13209)  (Show Source):
You can put this solution on YOUR website!
"...the probability that the  numbers not showing have a difference of 2 is"
(1) Tutor @ikleyn chose to say that your post is nonsense because of the missing plural. I'm a bit more forgiving than that; I know what you meant to say.
(2) The other tutor gave the wrong answer.
The number of possible outcomes for the numbers not showing on the two dice is 4*4=16.
Of those, 4 combinations (not 2) have a difference of 2: 1 and 3, 3 and 1; 2 and 4, 4 and 2.
ANSWER: P(difference of 2 between the two numbers not showing) = 4/16 = 1/4.
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