SOLUTION: The number of ways horses can finish first, second and third Instead, in a race involving n horses, it can be found through the expression: n (n - 1) (n - 2) a. Determine the n

Algebra ->  Probability-and-statistics -> SOLUTION: The number of ways horses can finish first, second and third Instead, in a race involving n horses, it can be found through the expression: n (n - 1) (n - 2) a. Determine the n      Log On


   

Question 1177301: The number of ways horses can finish first, second and third
Instead, in a race involving n horses, it can be found through the
expression:
n (n - 1) (n - 2)
a. Determine the number of ways the horses can finish first,
second and third place, in a race if 7 horses participate.
B. Rewrite the expression by multiplying the three factors.
C. Use the expression obtained in literal b to determine the number of ways in
that horses can finish first, second and third in a race
where 7 horses participate.
D. The results obtained in literal A and C ¿Are they the same?
Explain the answer.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
a. 7*6*5 = 210
b. n^3 - 3n^2 + 3n
c. n = 7, n^3 - 3n^2 + 3n = 217
d. NO
n (n - 1) (n - 2) is derived from 7P3, not intended to be used as in b.

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