SOLUTION: There are 11 green marbles, 5 blue marbles, and 6 red marbles in a jar. Three marbles will be drawn in succession without replacement. What is the probability that the marbles draw

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Question 1176601: There are 11 green marbles, 5 blue marbles, and 6 red marbles in a jar. Three marbles will be drawn in succession without replacement. What is the probability that the marbles drawn are a red marble, green marble, and a blue marble?
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
22 Marbles: 11G  5B  6R
3 drawn w/o replacement  22C3 ways this can be done.

P(R,G,B) =  (6/22)(11/21)(5/20)

Wish You the Best in your Studies.


Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

In total, there are 11 + 5 + 6 = 22 marbles in the jar.


    P = %2811%2F22%29%2A%285%2F21%29%2A%286%2F20%29 = %281%2F2%29%2A%285%2F21%29%2A%283%2F10%29 = %281%2F2%29%2A%281%2F21%29%2A%283%2F2%29 = %281%2F2%29%2A%281%2F7%29%2A%281%2F2%29 = 1%2F28.     ANSWER

Solved.