SOLUTION: PLEASE HELP ME SOLVE THIS, THANK YOU!
The performance of 50 teachers in the science department showed a
mean of 98 with standard deviation of 9.2. A sample of 40 teachers
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-> SOLUTION: PLEASE HELP ME SOLVE THIS, THANK YOU!
The performance of 50 teachers in the science department showed a
mean of 98 with standard deviation of 9.2. A sample of 40 teachers
from
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Question 1174775: PLEASE HELP ME SOLVE THIS, THANK YOU!
The performance of 50 teachers in the science department showed a
mean of 98 with standard deviation of 9.2. A sample of 40 teachers
from the English Department showed an average performance of 95
with a standard deviation of 7.3. Is there a difference in performance
between the two samples? Use a 0.05 level of significance. Answer by ewatrrr(24785) (Show Source):
Hi
Ho: p(S)-p(E) <= 0
Ha: p(S)-p(E) > 0 (claim)
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t[98-95] =
Find t-value and then p-value P( z > t-value) and compare to .05
Reject Ho if p-value is < .05
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