Question 1174102: In a large population, 64 % of the people have been vaccinated. If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?
Give your answer as a decimal (to at least 3 places) or fraction.
Found 3 solutions by ewatrrr, ikleyn, MathTherapy:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
In a large population, 64% of the people have been vaccinated.
If 4 people are randomly selected:
what is the probability that at least one of them has been vaccinated?
P( x≥ 1) = 1 - binomcdf(4, .64, 0) = 1 - .0168 = .983 (decimal to 3 places)
Wish You the Best in your Studies.
Solution works Great... with proper entering.
Answer by ikleyn(52780)  (Show Source):
You can put this solution on YOUR website! .
In a large population, 62% of the people have been vaccinated. If 4 people are randomly selected,
what is the probability that at least one of them has been vaccinated?
Give your answer as a decimal to 4 places.
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This probability is the COMPLEMENT to the probability of the event "No one of 4 has been vaccinated",
and THEREFORE is equal to 1 -  =  = 0.9791.
Solved.
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The solution and the answer by @ewatrrr are both incorrect.
.................
After seeing my post, @ewatrrr corrected her post --- now it is Ok.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! In a large population, 64 % of the people have been vaccinated. If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?
Give your answer as a decimal (to at least 3 places) or fraction.
I agree with tutor @IKLEYN that the other person is WRONG. I also agree with tutor @IKLEYN's setup of the problem, with the exception that
the success rate s/b 64% (.64) as opposed to 62% (.62), thereby making the answer: 0.98320384 ≈ 
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