SOLUTION: The average income of the residents of a particular community is your roll no *1000 and sd is your roll no *100: (a) What is the probability that income of a person, selected at r

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Question 1174090: The average income of the residents of a particular community is your roll no *1000 and sd is your roll no *100:
(a) What is the probability that income of a person, selected at random, is more than average income?
(b) What is the probability that income of a person, selected at random, is between average income and average income +2000?
(c) What is the probability that income of a person, selected at random, is bbetween average income+1000 and average income +2000?
(d) What is the probability that income of a person, selected at random, is less than average income +1000?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi,


Above is the Standard Normal Curve:  μ = 0  and  σ = 1  
Included are various z-scores demonstrating the AREA 
under the Standard Normal distribution Curve  according to the
value of a particular z-score.  

PROBABILITY of a particular x-value is an AREA as defined by z+=blue+%28x+-+mu%29%2Fblue%28sigma%29 
to the left of that z-score and is commonly written as P(z ≤ its value)
Whether one uses a z-score /table 0r a calculator, Probability will be
computed as representing an Area under the Standard Normal Curve.

In Your case:  μ = 1000  and  σ = 100 
(a) P(x > 1000) is the Area  to the right of  μ = 1000  
(According to the Above, obviously it is 50% of the Area under the curve 0r P = .50
    P (x > 1000) can be written as 1- P(x ≤ 1000) = .50

(b) P(1000 ≤ x < 1000) = P(1000 ≤ x ≤ 2000) = normalcdf(1000,2000,1000,100)
(c) P(1000 < x < 1000) = P(1000 ≤ x  ≤ 2000) = normalcdf(1000,2000,1000,100)

(d) P(x < 1000) =  P(x ≤ 1000) = .5
  
Wish You the Best in your Studies.