SOLUTION: In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean µ = 496 and a standard deviation σ = 114. Let X = a SAT exam

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Question 1173830: In 2012, 1,664,479 students took the SAT exam. The distribution of scores in the verbal section of the SAT had a mean µ = 496 and a standard deviation σ = 114. Let X = a SAT exam verbal section score in 2012. Then X ~ N(496, 114). -Billy scored 334. Find the z-scores for 334 to the nearest tenth. z=_________ -Xito scored 375. Find the z-scores for 375 to the nearest tenth. z=________ -Which student scored better based on their z score, Billy or Xito?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Normal Distribution:
µ = 496 , σ = 114

z = (334-496)/114 = -1.4 (nearest tenth)

z = (375 - 496)/114 = -1.1
Which student scored better based on their z score, Billy or Xito
-1.4 < -1.1 Billy z-score further away from the mean.
Wish You the Best in your Studies.

For the normal distribution:
one standard deviation from the mean accounts for about 68.2% of the set
two standard deviations from the mean account for about 95.4%
and three standard deviations from the mean account for about 99.7%.
Important to Understand z -values as they relate to the Standard Normal curve:

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