SOLUTION: A teacher has 20 boys and 10 girls in her class. In how many way can she select 6 of the children to be in a play if she must have 3 boys and 3 girls?
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-> SOLUTION: A teacher has 20 boys and 10 girls in her class. In how many way can she select 6 of the children to be in a play if she must have 3 boys and 3 girls?
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Question 1173263: A teacher has 20 boys and 10 girls in her class. In how many way can she select 6 of the children to be in a play if she must have 3 boys and 3 girls? Answer by ikleyn(52781) (Show Source):
The teacher can choose 3 boys from 20 boys by = = 1140 ways.
The teacher chooses 3 girls from 10 girls by = = 120 ways.
Since the selections in each category are independent, the entire choice can be done in 1140*120 ways = 136800 ways. ANSWER
Solved.
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This problem is on COMBINATIONS.
So, you should know what the combinations are and how to calculate them.
