SOLUTION: Two game tiles, numbered 1 through 9, are selected at random from a box without replacement. If their sum is even, what is the probability that both numbers are odd?

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Question 1172383: Two game tiles, numbered 1 through 9, are selected at random from a box without replacement. If their sum is even, what is the probability that both numbers are odd?
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
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If their sum is even, it means that EITHER both numbers are odd OR both numbers are even.


Among the numbers 1 to 9 inclusive, there are 5 odd and 4 even numbers.


So,  P(the sum is even) = P(both are odd) + P(both are even) = %285%2F9%29%2A%284%2F8%29+%2B+%284%2F9%29%2A%283%2F8%29 = 20%2F72+%2B+12%2F72 = 32%2F72.    


From the other hand side,  P(both are odd) = %285%2F9%29%2A%284%2F8%29 = 20%2F72.


Therefore, the conditional probability that both numbers are odd, given that their sum is even, is equal to


    P(final) = P%28both_are_odd%29%2FP%28the_sum_is_even%29 = %28%2820%2F72%29%29%2F%28%2832%2F72%29%29 = 20%2F32 = 5%2F8.    ANSWER

Solved.