SOLUTION: Out of 800 families having 4 children with the assumption that equal probabilities for boys and girls, how many families would be expected to have (i). 2 boys and 2 girls, (ii).

Algebra ->  Probability-and-statistics -> SOLUTION: Out of 800 families having 4 children with the assumption that equal probabilities for boys and girls, how many families would be expected to have (i). 2 boys and 2 girls, (ii).       Log On


   

Question 1169418: Out of 800 families having 4 children with the assumption that equal probabilities for
boys and girls, how many families would be expected to have (i). 2 boys and 2 girls, (ii).
at least 1 boy, (iii). at mot 2 girls and (iv). children of both sexes.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Number of ways of having 4 boys: C%284%2C4%29+=+1
Number of ways of having 3 boys (and 1 girl): C%284%2C3%29+=+4
Number of ways of having 2 boys (and 2 girls): C%284%2C2%29+=+6
Number of ways of having 1 boys (and 3 girls): C%284%2C1%29+=+4
Number of ways of having 0 boys (and 4 girls): C%284%2C0%29+=+1

Total number of possibilities: 1+4+6+4+1 = 16

P(4 boys) = 1/16
P(3 boys) = 4/16
P(2 boys) = 6/16
P(1 boys) = 4/16
P(0 boys) = 1/16

Use those probabilities to answer the specific questions in this problem.

Note in most cases, final answers should be in simplified fractions.