SOLUTION: Four players each are dealt one card. In how many ways could the cards all be clubs or honour cards (10, J, Q, K, A)?

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Question 1167284: Four players each are dealt one card. In how many ways could the cards all be clubs or honour cards (10, J, Q, K, A)?
Answer by Resolver123(6) About Me  (Show Source):
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There are 5 honor 'ranks' (10, J, Q, K, A), and each of these ranks has 4 suits. That means there are 5 x 4 = 20 honor cards.
In addition, there are 8 remaining 'clubs' cards (from 2 to 9), for a total of 20 + 8 = 28 cards satisfying the condition.
By the fundamental principle of counting, there are 28P4 = 28 x 27 x 26 x 25 = 491,400 ways of dealing one card to each player which is either a clubs or an honor card.