SOLUTION: the mean of n numbers is 5 if the number 13 is now included with n numbers the mean becomes 6 find the value of n

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Question 1166365: the mean of n numbers is 5 if the number 13 is now included with n numbers the mean becomes 6 find the value of n

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
%285n%29%2Fn=5
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cross%28%285n%2B13%29%2F6=6%29-------------solve this.
%285n%2B13%29%2F%28n%2B1%29=6---------------solve this.

Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
the mean of n numbers is 5 if the number 13 is now included with n numbers the mean becomes 6 find the value of n
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Let a%5B1%5D,  a%5B2%5D,  a%5B3%5D, . . . ,  a%5Bn%5D  be the given " n " numbers.


We are given that

    %28a%5B1%5D%2Ba%5B2%5D%2Ba%5B3%5D%2Bellipsis%2Ba%5Bn%5D%29%2Fn = 5.     (1)


It means that the sum  S%5Bn%5D = a%5B1%5D%2Ba%5B2%5D%2Ba%5B3%5D%2Bellipsis%2Ba%5Bn%5D  is equal to  5n


When the (n+1)-th number  a%5Bn%2B1%5D = 13 is included with n numbers, the mean of the (n+1) numbers is

    %28S%5Bn%5D%2B13%29%2F%28n%2B1%29 = 6.


It implies

    S%5Bn%5D%2B13 = 6(n+1),   

Replace here  S%5Bn%5D  by 5n, based on (1).  You will get

    5n + 13 = 6(n+1),

    5n + 13 = 6n + 6

    13 - 6  = 6n - 5n

     7      = n.


ANSWER.  n = 7.

Solved.

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The setup in the post by @josgarithmetic is INCORRECT;

so, for your safety, you better ignore it.