Question 1165680: A basketball player hits her free throws 80% of the time.
(a) Find the probability she misses for the second time on her 10th attempt.
(b) If she shoots 20 free throws, what is the probability she makes at least 19 of them?
(c) Assume that offensive fouls are equally likely to occur at any time during a game, and on
average 6 offensive fouls occur in a game. What is the probability of at least 8 offensive fouls occur in a
game.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Probability misses once in first 9 times is 9*0.8^8*0.2, the binomial formula. That is 0.3020.
The miss on the 10th has probability 0.2. That is multiplied by the first value to get 0.0604, the answer, assuming independence, which allows us to multiply these.
making all 20 is probability 0.8^20, or 0.0115.
making 19 is 20*0.8^19*0.2=0.0576
that sum is 0.0691
The last is Poisson, since no fixed trials, proportional to time and theoretically could be infinite. From the calculator, 7 or fewer has probability 0.7440, so the answer is the complement of 0.2560. It is more difficult doing it by hand from 8 on because need to do many more calculations until the value is insignificant, which is around P(15).
0.2560
|
|
|
