Question 1165343: A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a
fitness club go to their fitness center. Records of 244 members were looked at and their mean number of visits per week was 3.5 and the
standard deviation was 1.8.
I understand a and b, but need help with c.
a. To compute the confidence interval use a t distribution.
b. With 98% confidence the population mean number of visits per week is between 3.23 and 3.77 visits.
c. If many groups of 244 randomly selected members are studied, then a different confidence interval would be produced from each group.
About ______ percent of these confidence intervals will contain the true population mean number of visits per week and about_________
percent will not contain the true population mean number of visits per week.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! About 98% of the confidence intervals of samples of 244 will contain the true population mean number (the parameter) and about 2% will not contain the true population mean number. One doesn't know which 98, however, or which 2.
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