SOLUTION: Two hundred and fifty passenger have mad reservations for airplane flight. If the probability that a passenger who has a reservation show up is 0.98. what is the exactly five that

Algebra ->  Probability-and-statistics -> SOLUTION: Two hundred and fifty passenger have mad reservations for airplane flight. If the probability that a passenger who has a reservation show up is 0.98. what is the exactly five that       Log On


   

Question 1163265: Two hundred and fifty passenger have mad reservations for airplane flight. If the probability that a passenger who has a reservation show up is 0.98. what is the exactly five that will not show up?
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is  C%5B250%5D%5E5%2A%281-0.98%29%5E5%2A0.98%5E%28250-5%29 = %28%28250%2A249%2A248%2A247%2A246%29%2F%281%2A2%2A3%2A4%2A5%29%29%2A0.02%5E5%2A0.98%5E245 = 0.1772.    ANSWER


It is a binomial distribution problem 

with the number of trials n = 250 and the number of success trials of 245 = 250-5.

Solved.

------------------

To see many other similar solved problems, look into the lessons
    - Simple and simplest probability problems on Binomial distribution
    - Typical binomial distribution probability problems
in this site.