Question 1163217: Hi guys, I'm really stuck and need some help or a hint at least please. Thanks in advance! :)
A prisoner is trapped in a cell containing 3 doors. The first door leads to a tunnel that returns him to his cell after 2 days’ travel. The second leads to a tunnel that returns him to his cell after 4 day’s travel. The third door leads to freedom after 1 day of travel. If it is assumed that the prisoner will always select doors 1,2,and 3 with respective probabilities 0.5, 0.3, and 0.2, what is the expected number of days until the prisoner reaches freedom?
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website! <
Do you mean he's stupid enough to try the same door again which led him back
to the cell, hoping it won't lead him back to the cell like it did the first
time? Nobody is that stupid.
To avoid the necessity for such an insane prisoner, you ought to change the
problem so that the guard brings him a bag that has 5 red balls, 3 blue balls,
and 2 yellow balls. He draws a ball and its color determines how many days he
must wait before being allowed to draw again or to go free.
Edwin
|
|
|
