Question 1163005: The number of traffic accidents that occur on a particular stretch of road during a month follows a Poisson distribution with a mean of 7.4. Find the probability that fewer than three accidents will occur next month on this stretch of road
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! This is looking at 0,1,2 accidents with Poisson parameter 7.4
On the calculator, 2ndVARS C Poissoncdf ENTER (7.4,2), where the 2 is the largest value allowed. Probability is 0.0219
or P(0)=e^(-7.4)*7.4^0/0!=0.000611
P(1)=0.0045. the above answer *7.4^1/1, which is 7.4
P(2)=0.0167
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