SOLUTION: fruits weight is normally distributed with mean of 480 and standard deviation of 37. if you pick 23 at random,then 3% of their mean weight will be greater than how many grams
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Question 1161607: fruits weight is normally distributed with mean of 480 and standard deviation of 37. if you pick 23 at random,then 3% of their mean weight will be greater than how many grams
You can put this solution on YOUR website! z for 97th percentile is 1.881
z for this type of sampling distribution is (x bar-mean)/sigma/sqrt(n)
so
1.881=(x bar-480)*sqrt(23)/37
69.6/sqrt(23)=xbar-480=14.51
the mean weight will be greater than 494.5 grams in 3% of all possible samples of 23.
That's how I interpreted the problem.
If the author means 3% of the mean weight, or 14.835 grams is the answer. I've never seen that type of question before. I am assuming one wants the upper 3% of the distribution of mean weights.
