SOLUTION: A history class is comprised of 8 female and 5 male students. If the instructor of the class randomly chooses 5 students from the class for an oral exam, what is the probability th

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Question 1160471: A history class is comprised of 8 female and 5 male students. If the instructor of the class randomly chooses 5 students from the class for an oral exam, what is the probability that 3 female students and 2 male students will be selected? Round your answer to 3 decimal places.
Answer by ikleyn(52754) About Me  (Show Source):
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The answer is the ratio of two numbers.



The denominator is the number of all subsets of 8+5 = 13 persons, consisting of 3+2 = 5 persons;

    so; by the definition, it is the number of all combinations of 13 persons taken 5 at a time

        C%5B13%5D%5E5 = %2813%2A12%2A11%2A10%2A9%29%2F%281%2A2%2A3%2A4%2A5%29 = 1287.



The numerator is the number of all subsets, consisting of 3 females and 2 males.


    We can select 3 females of 8 female students by  C%5B8%5D%5E3 = %288%2A7%2A6%29%2F%281%2A2%2A3%29 = 8*7 = 56 ways;

    We can select 2 males of 5 male students by  C%5B5%5D%5E2 = %285%2A4%29%2F%281%2A2%29 = 5*2 = 10 ways.



Finally, the probability under the question is this number


    P = %2856%2A10%29%2F1287 = 0.43512 = 43.512%.      ANSWER

Solved.

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On Combinations,  see introductory lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.


On simple and simplest introductory lessons on Probability,  see the lessons
    - Simple and simplest probability problems
    - Solving probability problems using complementary probability
    - Elementary Probability problems related to combinations
    - A True/False test
    - A multiple choice answers test
    - Typical probability problems from the archive
    - Experimental probability problems
in this site.

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