SOLUTION: Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 75 women are randomly selected,
a) find the probab
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-> SOLUTION: Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 75 women are randomly selected,
a) find the probab
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Question 1159871: Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 75 women are randomly selected,
a) find the probability that they have a mean height between 63 and 65 inches.
b) find the probability that they have a mean height greater than 63.0 inches.
You can put this solution on YOUR website! z=(x-mean)/sigma/sqrt(n)
so z is between -0.6/2.5/sqrt(75) and 1.4/2.5sqrt(75)
this is between -2.078 and 4.85 so the probability is 0.9811
also 2nd VARS 2 normalcdf (63,65,63.6,(2.5/sqrt(75)) which is more exact and gives 0.9812 for the probability.
