SOLUTION: A TV manufacturer knows that their TV's have a normally distributed lifespan, with a mean of 5.5 years, and standard deviation of 0.8 years.
If a TV is picked at random, 3% of t
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-> SOLUTION: A TV manufacturer knows that their TV's have a normally distributed lifespan, with a mean of 5.5 years, and standard deviation of 0.8 years.
If a TV is picked at random, 3% of t
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Question 1159865: A TV manufacturer knows that their TV's have a normally distributed lifespan, with a mean of 5.5 years, and standard deviation of 0.8 years.
If a TV is picked at random, 3% of the time its life will be less than how many years?
Give your answer to one decimal place. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! This is the 3rd percentile, where z=-1.88
z=(x-mean)/sd
-1.88=(x-5.5)/0.8
x-5.5=-1.504
x=3.996 or 4.0 years.
