SOLUTION: Suppose that 𝑋 is normally distributed with mean 95 and standard deviation 16.
A. What is the probability that 𝑋 is greater than 119? Probability =
B. What value of 𝑋 d
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-> SOLUTION: Suppose that 𝑋 is normally distributed with mean 95 and standard deviation 16.
A. What is the probability that 𝑋 is greater than 119? Probability =
B. What value of 𝑋 d
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Question 1159523: Suppose that 𝑋 is normally distributed with mean 95 and standard deviation 16.
A. What is the probability that 𝑋 is greater than 119? Probability =
B. What value of 𝑋 does only the top 17% exceed?
I figured out part A and got 0.066807. However, I can't figure out part B. Please help Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Want the 83rd percentile and invnorm shows it to be. +0.9542, which is z
z=(x-mean)/sd
0.9542=(x-119)/16
x=110.26
