SOLUTION: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the

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Question 1159294: The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceed 76.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
z=(x-mean)/sd/sqrt(n)
z>=(76-75)/3.5/sqrt(49)
>=7/3.5=2
That probability of z>2 is 0.0228