Question 1158277: Two number cubes, each with the numbers 1 through 6, are rolled. What is the probability that the sum of the rolled numbers is 2?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
There is only one favorable outcome (1,1) of 6*6 = 36 possible outcomes,
all with the probability of  .
Therefore, the answer is P = .
Solved.
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If you want to learn this subject and this class of problems BETTER, DEEPER and WIDER, look into the lesson
- Rolling a pair of fair dice
in this site. You will find there many other similar solved problems.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Solved problems on Probability".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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What Alan wrote in his post, is a joke, as you understand.
Because these 11 outcomes for the sum go with DIFFERENT PROBABILITIES.
Thank you, Alan, for making us smile (!)
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Two number cubes, each with the numbers 1 through 6, are rolled. What is the probability that the sum of the rolled numbers is 2?
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The possible sums are the integers 2 thru 12 inclusive ---> 11 possibilities.
---> 1/11
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A 2 and a 5 gives the same sum as a 5 and a 2.
There are only 11 possible sums.
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