SOLUTION: there are 20 counters in bag x 11 of the counters are blue and the rest are red there are 16 counters in bay Y 9 of them are blue and the rest ed fancis take at random a counter fr

Algebra ->  Probability-and-statistics -> SOLUTION: there are 20 counters in bag x 11 of the counters are blue and the rest are red there are 16 counters in bay Y 9 of them are blue and the rest ed fancis take at random a counter fr      Log On


   



Question 1158222: there are 20 counters in bag x 11 of the counters are blue and the rest are red there are 16 counters in bay Y 9 of them are blue and the rest ed fancis take at random a counter from bag x and a random from bay Y wrok out the probabilty that the two counter are both red or are blue
Answer by ikleyn(52779) About Me  (Show Source):
You can put this solution on YOUR website!
.

    P = P(both red) + P(both blue) = %2811%2F20%29%2A%289%2F16%29 + %289%2F20%29%2A%287%2F16%29.


You calculate.