SOLUTION: Test the claim that the mean GPA of night students is significantly different than 2.9 at the 0.01 significance level. The null and alternative hypothesis would be: a)H0:p=0.7

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Question 1158219: Test the claim that the mean GPA of night students is significantly different than 2.9 at the 0.01 significance level.
The null and alternative hypothesis would be:
a)H0:p=0.725
H1:p≠0.725
b)H0:μ≥2.9
H1:μ<2.9
c)H0:p≥0.725
H1:p<0.725
d)H0:μ=2.9
H1:μ≠2.9
e)H0:μ≤2.9
H1:μ>2.9
f)H0:p≤0.725
H1:p>0.725
The test is:
a)two-tailed
b)left-tailed
c)right-tailed
Based on a sample of 60 people, the sample mean GPA was 2.9 with a standard deviation of 0.05
The p-value is:_______________(to 2 decimals)
Based on this we:
a)Fail to reject the null hypothesis
b)Reject the null hypothesis

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
H0 always has an "=" sign, never "<", ""≤", ">", "≥" or "≠".  Only
"H1" has those. So b), c), e), and f) are immediately eliminated.  That leaves 
only a) and d). It can't be a) because GPA is not a probability and p stands for
probability.  So the only choice left is d).    

That's the way to get it by elimination. But we could tell the answer without
using elimination because we are testing the mean 2.9, so it's H0:μ=2.9.

Also we are testing to see if μ is DIFFERENT from 2.9, not whether it is GREATER
or LESS than 2.9.  "DIFFERENT FROM means" "not equal to", "≠", because it could be
different from 2.9 it were either GREATER or LESS than 2.9. 

The test is: 

two-tailed because it's "≠", 

Based on a sample of 60 people, the sample mean GPA was 2.9 with a standard deviation of 0.05 
The p-value is:_______________(to 2 decimals) 

On your TI-84, press STAT
Highlight TESTS
Choose Z-Test

              Z-Test 
     Inpt:Data Stats        <---Highlight Stats
     μo:2.9
     σ:0.05
     x̄:2.9
     n:60
     μ:≠μooo  <--Highlight the first 
     Calculate              <--Highlight this

press enter

μ≠2.9
z=0
p=0.999999999
x̄=2.9
n=60

The p-value is 0.999999999 which rounds to 1.00 to 2 decimals

Based on this we fail to reject the null hypothesis, because p is greater than
0.01.

Remember the poem:

"If p is high, the null will fly."
"If p is low, the null must go."

If it "will fly", we fail to reject it.
If it "must go", we reject it.
In this case, p is "high" because it is more than the significance level 0.01 

Edwin